.1x^2+1=.5x

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Solution for .1x^2+1=.5x equation:


Simplifying
0.1x2 + 1 = 0.5x

Reorder the terms:
1 + 0.1x2 = 0.5x

Solving
1 + 0.1x2 = 0.5x

Solving for variable 'x'.

Reorder the terms:
1 + -0.5x + 0.1x2 = 0.5x + -0.5x

Combine like terms: 0.5x + -0.5x = 0.0
1 + -0.5x + 0.1x2 = 0.0

Begin completing the square.  Divide all terms by
0.1 the coefficient of the squared term: 

Divide each side by '0.1'.
10 + -5x + x2 = 0

Move the constant term to the right:

Add '-10' to each side of the equation.
10 + -5x + -10 + x2 = 0 + -10

Reorder the terms:
10 + -10 + -5x + x2 = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -5x + x2 = 0 + -10
-5x + x2 = 0 + -10

Combine like terms: 0 + -10 = -10
-5x + x2 = -10

The x term is -5x.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5x + 6.25 + x2 = -10 + 6.25

Reorder the terms:
6.25 + -5x + x2 = -10 + 6.25

Combine like terms: -10 + 6.25 = -3.75
6.25 + -5x + x2 = -3.75

Factor a perfect square on the left side:
(x + -2.5)(x + -2.5) = -3.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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